Darnell Henry Savage Jr. is an American football free safety for the Green Bay Packers of the National Football League. He played college football at Maryland and was drafted by the Packers in the first round of the 2019 NFL Draft.
As football lovers wish to know every detail about their loved and cheered players, questions were raised about the body measurement of Darnell Savage. In that regard, we discuss below his height and weight.
Height in meters and feet
Darnell can be considered an averagely tall sports personality by the height he stands at. He stands at a height of 5 feet and 11 inches, which when converted into meters, will be 1.80, or 180 centimeters.
Darnell attended Caravel Academy in Bear, Delaware. He suffered a broken femur during the first game of his junior season. He committed to the University of Maryland to play college football.
Weight in KG and lbs
With his height mentioned above, Darnell has a body mass proportional to it. He weighs 90 kg, which is equivalent to 198 lbs. Though his weight might change, we update you with the most recent check.
Darnell played at Maryland from 2015 to 2018. During his career, he had 182 tackles, eight interceptions, one sack, and two touchdowns.
He was drafted by the Green Bay Packers with the 21st overall pick in the first round of the 2019 NFL Draft. On May 2, 2019, Darnell signed a 4-year deal worth $12.5 million, including a signing bonus of $7.1 million.
Source: Ghanafuo.com
